Calculation Two

Instructions

Please attempt the calculation, then choose the best answer from those given and finally select the submit button to see whether you were correct.
Calculate the entropy changes at 25°C, for the following reactions:

Zn2+ + 2NH3 <=> [Zn(NH3)2]2+

ΔH = -28.03 kJ mol-1 and log10 β2 = 5.01

Zn2+ + en <=> [Zn(en)]2+

ΔH = -27.6 kJ mol-1 and log10 β = 6.15
(NB R=8.314 JK-1mol-1)
  1. -190, -214 JK-1mol-1
  2. 1.9, 25.2 JK-1mol-1
  3. -5.3, -4.1 JK-1mol-1
  4. 23, 300 JK-1mol-1
  5. None of these, or I don't know.
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